if 3 sin A = 4 cos A tan A = 4 /3 the value of tan 2 A - sec 2A =?
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Step-by-step explanation:
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Step-by-step explanation:
3 sin A = 4 cos A tan A=4/3
tan2A-sec2A
= tan2A-1/cos2A
=2tanA/(1-tan^2A) - (1+tan^2A)/(1-tan^2A)
=(2tanA-1-tan^2A)/(1-tan^2A)
=(1-tanA)^2/(1-tan^2A)
=(1-4/3)^2/(1-(4/3)^2)
=(-1/3)^2/(1-16/9)
=1/9/(-7/9)
= -1/7
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