Math, asked by vivajain, 6 months ago

if 3 sin A = 4 cos A tan A = 4 /3 the value of tan 2 A - sec 2A =?​

Answers

Answered by Vikas8271
3

Answer:

see the picture

Step-by-step explanation:

see the picture

Attachments:
Answered by sritarutvik
1

Step-by-step explanation:

3 sin A = 4 cos A tan A=4/3

tan2A-sec2A

= tan2A-1/cos2A

=2tanA/(1-tan^2A) - (1+tan^2A)/(1-tan^2A)

=(2tanA-1-tan^2A)/(1-tan^2A)

=(1-tanA)^2/(1-tan^2A)

=(1-4/3)^2/(1-(4/3)^2)

=(-1/3)^2/(1-16/9)

=1/9/(-7/9)

= -1/7

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