if 3 sin q = 4 cos q. find 4 sin. squar q - 3 cos squar q + 2
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Answer:
Given, 3sinq=4cosq
=>sinq/cosq=4/3 =>opposite side to q/adjacent side to q=4/3
Therefore, Opposite side to q=4; Adjacent side to q=3 Now,by Pythagorean theorem we get that Hypotenuse= 5 units Therefore, 4sin^2q-3cos^2q+2 = 4(4/5)^2-3(3/5)^2+2 =4(16/25)-3(9/25)+2 =(64-27+50)/25 =87/25 is the answer
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