If 3 sin theta - 4 cos theta = 2, then 4 cos theta + 3 sin theta =
(a)
![\sqrt{21} \sqrt{21}](https://tex.z-dn.net/?f=+%5Csqrt%7B21%7D+)
(b)
![\sqrt{22} \sqrt{22}](https://tex.z-dn.net/?f=+%5Csqrt%7B22%7D+)
(c)
![\sqrt{8} \sqrt{8}](https://tex.z-dn.net/?f=+%5Csqrt%7B8%7D+)
(d) None of these
Answers
Answered by
1
Answer:
It should be root twenty two.
Similar questions