If 3 sin theta - 4cos theta = 0 find value of tan theta
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Answer:
3sin θ - 4 cos θ = 0
3sin θ = 4cos θ
sin θ/cos θ = 4/3
tan θ = 4/3.
NOTE : tan θ is positive,so θ is in the 1st and 3rd quadrants.
sec^2 θ = 1 + tan^2 θ
sec^2 θ = 1 + 16/9 = 25/9
sec θ = +/- 5/3.
NOTE:
sec θ +ve,θ in the 1st & 4th quadrants.
sec θ -ve,θ in the 2nd & 3rd quadrants.
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