Question

if √3 sin theta - cos theta=0and 0°<theta<90°; find value of theta​

Answer 1

Answer:

$\sqrt{3} sin \theta - cos \theta = 0 \: \: \: 0 \degree< \theta < 90 \degree \\ \implies \: \sqrt{3} sin \theta = cos \theta \\ \implies \frac{sin \theta}{cos \theta} = \frac{1}{ \sqrt{3} } \\ \implies \: tan \theta = \frac{1}{ \sqrt{3} } \\ \implies \theta = \frac{\pi}{6}$