Question

If 3 sin thita-4 cos thita=0 find the values of tan thita and sec thita​

Answer 1

Answer:

Step-by-step explanation:

3sinβ - 4cosβ = 0

3sinβ = 4cosβ

3 $\frac{sin\beta }{cos\beta }$ = 4

$\frac{sin\beta }{cos\beta }$ = $\frac{4}{3}$

tanβ = $\frac{4}{3}$

sec²β = tan²β + 1

sec²β = $\frac{16}{9}$ + $\frac{9}{9}$ = $\frac{25}{9}$

secβ = ± $\frac{5}{3}$