If √3 sin x-cos x = 0 and 0° < x
< 90°, find the value of x
Answers
Answered by
0
Answer:
30°
Step-by-step explanation:
√3sinx = cosx
tanx=1/√3
here, x (0° to 90°)
so,
x=30°
Answered by
0
Answer:
Root3si nx=cosx
Sinx/cos =1/root3
Step-by-step explanation:
Tanx=tan(pie/6) so x=pie/6
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