Math, asked by vyshuvyshnavi, 1 year ago

If √3 sin x-cos x = 0 and 0° < x
< 90°, find the value of x​

Answers

Answered by ramanujan67
0

Answer:

30°

Step-by-step explanation:

√3sinx = cosx

tanx=1/√3

here, x (0° to 90°)

so,

x=30°

Answered by vishalkumar2957
0

Answer:

Root3si nx=cosx

Sinx/cos =1/root3

Step-by-step explanation:

Tanx=tan(pie/6) so x=pie/6

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