If 3 sinA =1 then value of 2cosAcosecA
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3sinA = 1
sinA= 1/3
cosA = √8/3
cosA.cosecA = √8/3 * 3
= √8 = 2√2
hope it helps you
Answered by
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Answer:
3sinA = 1
sinA =1/3
As sinA = P/H = 1/3
AS we know sides are proportional in triangle ,
So, take P= 1, H=3
B= √(H)^2-P^2
=√((3)^2 -1 )
=√(9-1 )
=√8
=2√2
So, 2Cos A cosecA
= 2cos A . 1/sinA
= 2 cotA
As cotA = B/P
hence cotA = 2√2
So, 2cosA cosecA = 2 cotA
=2(2√2)
=4√2
#answerwithquality #BAL
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