if 3 sinQ + 5 Cos Q = 5
then
5 sin Q - 3 Cos Q=?
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Guys if i answer correct then please mark me as brainliest..
Given: 3sinQ+5CosQ=5
Squaring on both sides, we get:
(3sinQ+5cosQ)² =(5)²
9sin²Q+25cos²Q+30sinQcosQ=25
9sin²Q+25(1-sin²Q)+30sinQcosQ=25
9sin²Q+25-25sin²Q+30sinQcosQ=25
9sin²Q-25sin²Q+30sinQcosQ=0
9(1-cos²Q)-25sin²Q+30sinQcosQ=0
9-9cos²Q-25sin²Q+30sinQcosQ=0
-9cos²Q-25sin²Q+30sinQcosQ=-9
Taking minus as common
-(9cos²Q+25sin²Q-30sinQcosQ)= -9
Cancelling minus from both sides
(9cos²Q+25sin²Q-30sinQcosQ)=9
{ (3cosQ)²+(5sinQ)²-2(3cosQ)(5sinQ) } =9
(5sinQ-3cosQ)²=9
5sinQ-3cosQ=√9
5sinQ-3cosQ=3
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