If √3 sinx+cosx=2 then find the value of x
Answers
Answered by
0
Answer:
x = π/3
Step-by-step explanation:
√3×sinx+cosx=2
✓3×sinx=2-cosx
sq on b/s
3sin²x = 4+4(-cosx)+cos²x
cosx = -4/-8
cosx = 1/2
x= cos^-1(1/2)
x = π/3
Answered by
0
Answer:
π/3
Step-by-step explanation:
√3sinx=2-cosx
(√3sinx)^2= (2-cosx)^2
3sin^2x=4-4cosx+cos^2x
3(1-cos^2x)= 4-4cosx+cos^2x
3-3cos^2x=4-4cosx+cos^2x
4cos^2x-4cosx+1=0
(2cosx-1)^2=0
2cosx-1=0
2cosx=1
cosx=1/2
x= π/3
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