Math, asked by mafikurrahaman731219, 11 months ago

If √3 sinx+cosx=2 then find the value of x

Answers

Answered by Anonymous
0

Answer:

x = π/3

Step-by-step explanation:

√3×sinx+cosx=2

✓3×sinx=2-cosx

sq on b/s

3sin²x = 4+4(-cosx)+cos²x

cosx = -4/-8

cosx = 1/2

x= cos^-1(1/2)

x = π/3

Answered by afifahumayra77
0

Answer:

π/3

Step-by-step explanation:

√3sinx=2-cosx

(√3sinx)^2= (2-cosx)^2

3sin^2x=4-4cosx+cos^2x

3(1-cos^2x)= 4-4cosx+cos^2x

3-3cos^2x=4-4cosx+cos^2x

4cos^2x-4cosx+1=0

(2cosx-1)^2=0

2cosx-1=0

2cosx=1

cosx=1/2

x= π/3

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