Question

if 3 tan #-2 sin²#=2 cos²# then find the value of 3 sin #-3 cos# /7 sin #+ 14 cos#

# = thita​

Answer 1

Answer:

Bhai brainliest mark karde bohot mehnat lagi hai

Answer 2

Answer:

-3/56

Step-by-step explanation:

given -

3 tan # = 2( sin^2# + cos^2#)

3 tan # = 2

tan # = 2/3

now sin # = 2/√13

cos # = 3 / √13

to find ( 3sin # - 3cos #) / ( 7sin # + 14 cos # )

= ( 6/√13 - 9/√13) / ( 14/√13 + 42/√13)

= -3/56

hope it helps...