If 3 tan^2 theta - 4√3 tan theta + 3= 0. Then find theta.
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Jazza26:
thank you very much!!!
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Step-by-step explanation:
3tan^-4√3tan thta + 3=0
theta = t.
let,
3t^-4√3+3=0
3t^-3√3t-√3+3=0
3t ( t - √3) -√3 ( t - √3)=0
(3t - √3) (t-√3) =0
3t-√3=0 & t-√3=0
t=√3/3 & t = √3
t = 1/√3....
tan theta = 1/√3 or tan theta =√3
theta = 30° or than theta =60°
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