if √3 tan 20 =3 and 0°<∅<90° find the value of 3√3 cos 0 + 2 sin - 6 tan²∅
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Answer:
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Answered by
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Step-by-step explanation:
Given expression is
sin20
∘
3
−
cos20
∘
1
=2(
sin20
∘
3
/2
−
cos20
∘
1/2
)
=2(
sin20
∘
sin60
∘
−
cos20
∘
cos60
∘
)
=2(
sin20
∘
cos20
∘
sin60
∘
cos20
∘
−cos60
∘
sin20
∘
)
=2(
sin20
∘
cos20
∘
sin(60
∘
−20
∘
)
)
=2
sin20
∘
cos20
∘
sin40
∘
=2×
sin20
∘
cos20
∘
2sin20
∘
cos20
∘
=4
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15
SIMILAR QUESTIONS
star-struck
The value of cos66
∘
+sin84
∘
is
Medium
View solution
>
I: 4(sin24
∘
+cos6
∘
)=
15
+
3
II: sin21
∘
cos9
∘
−cos84
∘
cos6
∘
=
4
1
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