If √3 tan θ = 3 sin θ , find the value of sin²θ - cos²θ . Pls with steps!!!
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Answer:
1/3.
Step-by-step explanation:
Given: √3 tan θ = 3 sinθ
⇒ √3 (sinθ/cosθ) = 3 sinθ
⇒ √3/cosθ = 3
⇒ (1/cosθ) = 3/√3
⇒ cosθ = (1/√3)
⇒ cos²θ = (1/3).
Now,
∴ sin²θ + cos²θ = 1
⇒ sin²θ + (1/3) = 1
⇒ sin²θ = 2/3
Value of sin²θ - cos²θ
= (2/3) - (1/3)
= 1/3
Hope it helps!
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