Question

If 3 tan α = 4 ,and 2 SEᑕ α = 3 k+ 1 ,then find k if α is acute .
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Answer 1

Step-by-step explanation:

3 tanα=4

tanα= 4/3

secα= 3k+1

We know that sec²-tan²=1

so,

(3k+1)²-(4/3)²=1

(3k+1)²= 1+(4/3)²

(3k+1)²= 1+16/9

(3k+1)²= 25/9

on taking root both side we get

3k+1= ±5/3

3k+1= 5/3

3k= 5/3-1

3k= 2/3

k= 2/9

3k+1= -5/3

3k= -5/3-1

3k= -8/3

k= -8/9

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