If 3 tan θ – 4 cot θ = 0, then cot θ = ?
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Step-by-step explanation:
ANSWER
Given,
3tan(θ)=cot(θ)
3tan(θ)−cot(θ)=0
−
sin(θ)
cos(θ)
+3⋅
cos(θ)
sin(θ)
=0
cos(θ)sin(θ)
−cos
2
(θ)+3sin
2
(θ)
=0
−cos
2
(θ)+3sin
2
(θ)=0
(
3
sin(θ)+cos(θ))(
3
sin(θ)−cos(θ))=0
3
sin(θ)+cos(θ)=0:θ=
6
5π
+πn
3
sin(θ)−cos(θ)=0:θ=
6
π
+πn
θ=
6
5π
+πn,θ=
6
π
+πn
∴θ=150
∘
,30
∘
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