Question

if 3 tan A =4, then find Sin A =​

Answer 1

Explanation:

3 tan A = 4

tan A = 4/3

opp/adj= 4/3

opp=4 and adj= 3

hypotanuse=

$\sqrt{( {3}^{2} + {4}^{2} } )$= 5

sin A= opp/hypotanuse= 4/5

Answer 2

Answer:

tanA = 4/3

tanA = P/B

p= 4

b=3

h=

$\sqrt{( {p})^{2} + ( {b})^{2} }$

$= \sqrt{16 + 9}$

$= 5$

sinA =p/h=4/5