Question

If 3 tan A = 4, then find sin A and cos A.
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Answer 1

Answer:

3tanA=4

tanA=4/3

Since,tan=P/B

Hence,P=4

B=3

H=√(P^2+B^2)

√(4*4+3*3)

√(16+9)

√25

5

Now,

sinA=P/H

4/5

cosA=B/H

3/5