Question

if 3 tan A =4 then find sin A and cos A​

Answer 1

Answer:

Let ABC is a right angle triangle

3tanA=4 ⇒tanA=

3

4

=

AB

BC

By using Pythagoras theorem

AC

2

=AB

2

+BC

2

=(3)

2

+(4)

2

=9+16=25

∴AC=

25

=5

sinA=

Hypotenuse

Opposite side of∠A

=

AC

BC

=

5

4

∴cosA=

Hypotenuse

Adjacent side of∠A

=

AC

AB

=

5

3

∴sinA=

5

4

and cosA=

5

4

Answer 2

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