Question

If 3 tan A = 4, then find sin A and cos A.

Answer 1

TanA= 3/4 By using Pythagoras Theorem: AB^2+BC^2=AC^2 4^2+3^2=AC^2 AC=5 So, SinA=3/5 CosA=4/5  

Answer 2

3tanA=4, tanA=4/3
tanA=p/b
by p.t
$h ^{2} = b ^{2} + h ^{2}$
$h ^{2} = 3 ^{2} + 4^{2}$
=16+9
=25
=
$\sqrt{25 }$
=5
so h=5
sinA =p/h
=4/5
cosA=b/h
=3/5
hope it help you