Question

If 3 tan A=4, then find sin A and cos A. Y are acute angles such that cos A​

Answer 1

Sec2x-tan2x=1
tanx=4/3(given)
tan2x=16/9
Sec2x=1+tan2x
Sec2x=1+(16/9)=25/9
Secx =root of (25/9)=5/3
Cosx=1/secx=3/5

Cos2x+sin2x=1
Sin2x=1-cos2x
Sin2x=1-(9/25)=16/25
Sinx=4/5

Answer
cosx=3/5
sinx=4/5