If 3 tan A=4, then find sin A and cosA
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Answer:
i hope it helps
Step-by-step explanation:
Let ABC is a right angle triangle
3tanA=4 ⇒tanA=
3
4
=
AB
BC
By using Pythagoras theorem
AC
2
=AB
2
+BC
2
=(3)
2
+(4)
2
=9+16=25
∴AC=
25
=5
sinA=
Hypotenuse
Opposite side of∠A
=
AC
BC
=
5
4
∴cosA=
Hypotenuse
Adjacent side of∠A
=
AC
AB
=
5
3
∴sinA=
5
4
and cosA=
5
4
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