If 3 tan A = 5 , then (3 SinA- 5 Cos A) / ( 3 Sin A + 5 Cos A)
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Answer:
Given,
3 tan A= 5
tan A = 5/3
.°. tan A = Perpendicular/ Base =5/3
By Phythagoras theorem---
H^2= P^2 + B^2
= (5)2 + (3)2
= 25 + 9
= 34
H= √34
According to the questions,
sinA = 5/ √34
cos A= 3/√34
=( 3x 5/34 -5 x 3/√34) / (3x 5/√34 + 5x 3/√34)
=( 15/√34 - 15/√34) / (15/√34 +15/√34)
= 0 / 30/√34
=0
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