If √3 tan theta = 3sin theta then find the value of sin^2 theta - cos^2 theta
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The value of sin² θ - cos² θ = 1/3
Given:
√3 tan θ = 3 sin θ
To find:
The value of sin² θ - cos² θ
Solution:
Given √3 tan θ = 3 sin θ
as we know tan θ = (sin θ/cos θ)
⇒ √3 (sin θ/cos θ) = 3 sin θ
⇒ √3 (1 /cos θ) = 3
⇒ cos θ = √3 /3
⇒ cos θ = √3 /(√3√3) [ ∵ √3(√3) = 3 ]
⇒ cos θ = 1 /√3
As we know sin² θ = 1 - cos² θ
⇒ sin² θ = 1 - (1/√3)² = 1-1/3 = 2/3
⇒ sin² θ - cos² θ = (2/3) - 1/3 = 1/3
The value of sin² θ - cos² θ = 1/3
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