Question

if √3 tan theta=3sin theta, then prove that sin²theta-cos²theta =1/3

Answer 1

Answer:

sorry I don't know this question

Answer 2

Step-by-step explanation:

cosθ

3

sinθ

=3sinθ

secθ=

3

∴cosθ=

3

1

⇒cos

2

θ=

3

1

sin

2

θ+cos

2

θ=1−cos

2

θ−cos

2

θ=1−2cos

2

θ ...[∵sin

2

θ=1−cos

2

θ]

=1−2(

3

1

)=1−

3

2

=

3

1