Question

if 3 tan theta =4 find the value of 4cos theta - sin theta by 2 since theta +6 cos theta

Answer 1

tan(?)=4÷3
​sec(?)=5÷3​
cos(?)=3÷5​
sin(?)=4÷5​​​
ans is
= 4÷13

Answer 2

Hiii,

3tan theta = 4
tan theta = 4/3= p/b
p= 4 , b= 3 , h= ?
we know that,
h²= (p)²- (b)²
h²= (4)²-(3)²
h²= 16-9= 7
h= ✓7.
Therefore,
sin theta = p/h = 4/✓7
cos theta = b/h = 3/✓7
Therefore,
=4Cos theta - Sin theta /2 Sin theta+ 6 Cos theta.
= 4×(3/✓7)- (4/✓7)/2(4/✓7)+6(3/✓7)= 4/13

HOPE IT WILL HELP YOU..