if √3 tan theta is equal to 3 sin theta then find sin²-cos²
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Answered by
96
answer is 1/3?
if it is correct then tell me i will justify my answer:)
√3 tanФ= 3sinФ
√3sinФ/cosФ=3 sinФ
√3×1/cosФ=3
√3=3 cosФ
cosФ=√3/3
cosФ=base/hypotenuese
then base =√3 units
perpendicular=3 units
then (height)² =(hypotenuese)²-(base)²
=(3)²-(√3)²
=9-3
∴height =√6
sinФ=perpendicular/hypotenuese
=√6/3
sin²Ф-cos²Ф
⇒(√6/3)²-(√3/3)²
⇒6/9-3/9
⇒3/9
=1/3
if it is correct then tell me i will justify my answer:)
√3 tanФ= 3sinФ
√3sinФ/cosФ=3 sinФ
√3×1/cosФ=3
√3=3 cosФ
cosФ=√3/3
cosФ=base/hypotenuese
then base =√3 units
perpendicular=3 units
then (height)² =(hypotenuese)²-(base)²
=(3)²-(√3)²
=9-3
∴height =√6
sinФ=perpendicular/hypotenuese
=√6/3
sin²Ф-cos²Ф
⇒(√6/3)²-(√3/3)²
⇒6/9-3/9
⇒3/9
=1/3
Aksha02:
yes correct but i need the steps
Answered by
3
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