if 3 tan theta is equals to 4 evaluate 3 sin theta + 2 cos theta by 3 sin theta minus 2 cos theta
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Hope this will help you!!!
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yugayush:
its more useful thanks
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my friend ,
tanФ=4/3=opposite side / adjacent side
therefore ,by applying pythagorean theorem we get ,
(4)^2+(3)^2=(hypotenuse )^2
hypotenuse =5cm
therefore ,
by finding the hypotenuse we can say that
sin∅=4/5=opposite side /hypotenuse
cos∅=3/5=adjacent side /hypotenuse
3sin∅+2 cos ∅=3(4/5)+2(3/5)=12/5+6/5=18/5
3sin∅-2cos∅=12/5-6/5=6/5
therefore
=(18/5)/6/5
=18/6=3
tanФ=4/3=opposite side / adjacent side
therefore ,by applying pythagorean theorem we get ,
(4)^2+(3)^2=(hypotenuse )^2
hypotenuse =5cm
therefore ,
by finding the hypotenuse we can say that
sin∅=4/5=opposite side /hypotenuse
cos∅=3/5=adjacent side /hypotenuse
3sin∅+2 cos ∅=3(4/5)+2(3/5)=12/5+6/5=18/5
3sin∅-2cos∅=12/5-6/5=6/5
therefore
=(18/5)/6/5
=18/6=3
pls mark it as brainiest answer
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