Question

If 3 tan (x-15°) = tan (x + 15°), 0 < x< 90°, then prove that x = 45°.​

Answer 1

${\huge {\mathfrak {Answer :-}}}$

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3 tan (x - 15) = tan (x + 15)

Or, 3 = tan (x + 15) / tan (x - 15)

Or, 3 = tan (x + 15) × cot (x - 15)

Or, $\sqrt {3} \times \sqrt {3}$ = tan (x + 15) × cot (x - 15)

Or, tan 60 × cot 30 = tan (x + 15) ×

cot (x - 15)

Or, x + 15 = 60 and x - 15 = 30.

Or, x = 45.

Therefore, x = 45 °

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