if √3 tan x = 3 sin x, find the value of sin² x- cos²x
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Soln:
Given,
√3 tan x = 3 sinx
sin² x- cos²x=?
Now,
√3 tan x = 3 sin x
or, √3sinx/cosx=3sinx
or, √3/3=sinx.cosx/sinx
:.1/√3=cosx
Again,
Putting value of cosx, we get;
sin² x- cos²x
=(1-cos²x)-cos²x :. sin²x= (1- cos²x)
={1-(1/√3 )²}-(1/√3 )²
=1-(1/3)-(1/3)
=(3×1-1×1-1×1)/3 :. Taking 3 as L.c.m.
=(3-1-1)/3
=1/3
:. sin² x- cos²x=1/3.
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