Question

if √3 tanA = 3 sinA prove that sin²A- cos²A = 1/3​

Answer 1

Answer:

√3 tanA = 3sinA √3sinA/ cosA = 3 sinA cosA = √3/3 sin² A = 1-cos²A = 1 -(√3/3)² = 1- 3/9 =1-1/3 = 2/3 Sin²A-cos²A ...

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