Question

If 3 tanA= 4 Then find sinA cosA

Answer 1

Answer:

3 tan A=4

=> tan A=4/3

=> sec^2A=1+tan^2A

=1+16/9

=25/9

=> sec A =5/3

=> cos A=3/5

sin^2A=1-cos^2A

=1-9/25

=16/25

=> sin A=4/5

so, sin A=4/5 and cos A=3/5

Answer 2

3tanA = 4 as given.

tanA = 4/3

Now, we'll find sinAcosA.

We know that tanθ = p/b

tanA = p/b = 4/3

Using Pythagoras Theorem,

h² = b² + p²

h² = 9 + 16

h² = 25

h = 5

sinA = p/h

sinA = 4/5

cosA = b/h

cosA = 3/5

∴sinAcosA = (4)/(5) × (3)/(5)

. = 12/25