If 3 times the 3rd term of an AP is equal to 7 times 7th term then find the 10th term. plzz a quick answer..........................
Answers
Answered by
3
Hey.... I think this can be ur answer!!
3T3= 7T7
3(a+2d)=7(a+6d)
3a+6d = 7a + 42d
-4a=36d
-a=9d......
Now,
T10 = a+ 9d
=a - a
=0
3T3= 7T7
3(a+2d)=7(a+6d)
3a+6d = 7a + 42d
-4a=36d
-a=9d......
Now,
T10 = a+ 9d
=a - a
=0
yatiawasthi177:
thank you so much
Answered by
1
Let the first term of the AP be a and common difference be d.
then, 3(3rd term) = 7(7 th term)
or, 3(a+2d) = 7(a+6d)
or, 3a-7a = 42d- 6d
or, -4a = 36d
or, 4a+36d = 0
or, 4(a+ 9d) = 0
or, (a+9d) = 0
Hence T10 = 0
So, 10th term will be zero.
Hope it helped.
plss mark as brainliest.
then, 3(3rd term) = 7(7 th term)
or, 3(a+2d) = 7(a+6d)
or, 3a-7a = 42d- 6d
or, -4a = 36d
or, 4a+36d = 0
or, 4(a+ 9d) = 0
or, (a+9d) = 0
Hence T10 = 0
So, 10th term will be zero.
Hope it helped.
plss mark as brainliest.
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