if 3 times the third term of an A.P is equal to 5 time the fifth term. then it's 8th term is?
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Answer:
Tn=a+(n-1)d
Tn=nth term
a=first number
d=common difference(difference between consecutive terms)
T3=a+(3-1)d
=a+2d
T5=a+(5-1)d
=a+4d
3(T3)=5(T5)
3a+6d=5a+20d
or, 3a-5a=20d-6d
or, -2a=14d
or, a=14d/(-2)
therefore, a=(-7d)
T8=a+(8-1)d=a+7d
= -7d+7d=0
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