Question

If 3 to the power of 1989 is divided by 7 Then remainder is

Answer 1

$1983 \times 1983 \times 1983 \div 7$
$1983 \times 1983 \times 1983 = 7797729087$
$7797729087 \div 7 = 1113961298.1428$
Therefore remainder is
1

Answer 2

Thank you for asking this question. The options for this question are missing. Here are the missing options:

A. 1

B. 5

C. 6

D. 4

E. 3

Answer:

3 / 7 remainder = 3

3^2 = 9 / 7 remainder = 2

3 ^ 3 = 27 / 7 remainder = 6 or -1 (equation 1)

1989/3 = 663

From the equation 1 above,

3 ^ 1989 = (3^3) ^ 663 ;

rem = (-1) ^ 663 = -1 or 6  

So the final answer for this question is Option C: 6

If there is any confusion please leave a comment below.