If|Ā = 3 units, B = 4 units and the angle between vectors A and B is 90°, then the magnitude and direction of resultant R with vector A are O ( (a) R = 25 units and tan d = 4/3 O (b) R = 5 units and tan 0 = 4/3 O (c) R = 25 units and tan 0 = 3/4 O (d) R = 5 units and tan $ = 3/4
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Pleasemark Brainlist
Explanation:
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Concept:
- Vector addition
- Pythagoras' theorem
Given:
- The magnitude of Vector A, A = 3
- The magnitude of vector B, B = 4
- Angle theta between the vectors A and B = 90°
Find:
- The magnitude of the resultant vector
- The direction of the resultant vector
Solution:
The magnitude of a resultant vector is the square root of the sum of the squares of the two individual vectors that are perpendicular to each other
R = √(A^2 +B^2)
R = √(3^2 +4^2)
R = √(9 + 16)
R = √(25)
R = 5 units
To find the direction, we know that tan theta = y/x = 3/4
Theta = arctan 3/4 = 37°
The magnitude of the resultant is 5 units and the direction is 37°.
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