if 3 upon x + 4 upon y = 18 , 5 upon x + 6 upon y equals 28 then x minus y =
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(i) 1 and x + 3 5 y +3 6 E. 6x –59 + 3 = 0 ...(ii) 1 On comparing with equation ax + by + c = 0. we get a1 = 11, b = -9, c1 = 4, and a2 = 6, ...
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Given: 3/x+4/y=18,5/x+6/y=28
To find: x+y
Sol: Let 1/x be a and 1/y be b
Therefore 3a+4b=18............(1)
And 5a+6b=28.............(2)
From(1), a=18-4b/3........(3)
Putting a in (2), we get
5(18-4b/3) +6b=28
(90-20b/3) +6b=28
90-20b+18b=28b
90-2b=28b
90-30b=0
90=30b
b=3
Putting b=3 in (3)
a=18-12/3
a=6/3
a=2
Now,1/x=a
1/x=2
x=1/2
Also, 1/y=b
1/y=3
y=1/3
Therefore, x+y=1/2+1/3
x+y=3+2/6
x+y=5/6
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