if 3^x+1=9^x-2, find 2^x+1
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Answer:
3^x+1 =9^x-2
[*9=3^2 then the 9^x-2 will become as 3^2x-4]
3^x+1=3^2x-4
[As the bases are same and the power are different, cancel the 3 on either side]
then
x+1=2x-4
2x-x=4+1
X=5
Now,
2^x+1
=2^5+1
=2^6
=64
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