Question

If 3^x+^1 = 9^x - ^3, find the value of 2^1+ ^x​

Answer 1

Answer:

Step-by-step explanation:

3^(x+1)=9^(x-3)

3^(x+1)=3^(2x-6)

by removing 3 on both sides we get

x+1=2x-6

6+1=2x-x

x=7

then

2^(1+x)

2^(1+7)

2^8

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