if 3 X + 2 Y = 12 and xy = 6 find the value of 27 x cube + 8 y cube
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Step-by-step explanation:
(3x+2y)^3=12^3
27x^3+8y^3+3.3x.2y(3x+2y)=1728
27x^3+8y^3+18xy.12=1728
27x^3+8y^3+18.6.12=1728
27x^3+8y^3+1296=1728
27x^3+8y^3=1728-1296
27x^3+8y^3=432
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