if 3 X + 2 Y is equal to 12 and X Y is equal to 6 find the value of 9 X square + 4 y square
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Answered by
7
- we need to find the value of 9x² + 4y²
- 3x + 2y = 12
- xy = 6
we know that,
⇝ (a + b)² = a² + b² + 2ab
⇝ a² + b² = (a + b)² - 2ab
Then,
- Value of 9x² + 4y² is :-
Let
- a = 3x
- b = 2y
Then,
⇝ 9x² + 4y² = (3x + 2y)² - 2× 3x × 2y
we know that,
- 3x + 2y = 12
- xy = 6
Then,
⇝ 9x² + 4y² = 12² - 12 × 6
⇝9x² + 4y² = 144 - 72
⇝9x² + 4y² = 72
Hence,
- Value of 9x² + 4y² is 72
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Answered by
2
Answer:56
Step-by-step explanation:As per question 3x+2y=12...........1eqn
xy=6................2eqn
9x^2+4y^2=?
From second equation we can get x =6/y
Putting the value of x in equation first
3(6/y)+2y=12
18+2y^2=12y
2y^2-12y+18=0
2y^2-6y-6y+18=0
2y(y-3)-6(y-3)=0
(2y-6)(y-3)=0
y=3,3
Putting the value of y in x=6/y
x=6/3=2
Thus putting value in equation 3
9(2)^2+4(3)^2=9*4+4*9=28+38=56
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