Question

if 3√x+(3√3375) ^3 =17.then find the cube root of x-1026 equal to​

Answer 1

Answer:

Step-by-step explanation:

Answer is 8

Answer 2

SOLUTION :-

GIVEN :-

$\sf{ \sqrt[3]{x + { \bigg( \sqrt[3]{3375} \bigg)}^{3} } = 17 }$

TO DETERMINE :-

$\sf{ \sqrt[3]{x - 1026} }$

EVALUATION :-

Here it is given that

$\sf{ \sqrt[3]{x + { \bigg( \sqrt[3]{3375} \bigg)}^{3} } = 17 }$

Taking cube in both sides we get

$\sf{ {x + { \bigg( \sqrt[3]{3375} \bigg)}^{3} } = {(17)}^{3} }$

$\implies \sf{ {x + { \big( 15 \big)}^{3} } = 4913 }$

$\implies \sf{ x + 3375 = 4913 }$

$\implies \sf{ x = 4913 - 3375 }$

$\implies \sf{x = 1538}$

$\therefore \: \: \: \sf{ \sqrt[3]{x - 1026} }$

$= \sf{ \sqrt[3]{1538 - 1026} }$

$= \sf{ \sqrt[3]{512} }$

$= \sf{ \sqrt[3]{(8 \times 8 \times 8)} }$

$= \sf{8}$

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