if 3 x - 4 Y = 12 and XY= 6 find 27x^3 -64^3
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We have to find 27x^3 - 64y^3 right?
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Using Identity : (a - b)³ = a³ - b³ - 3ab(a - b)
We get,
(3x - 4y)³ = (3x)³ - (4y)³ -3(3x)(4y)(3x - 4y)
⇒ 12³ = 27x³ - 64y³ - 36xy(12)
⇒ 1728 = 27x³ - 64y³ - 36(6)(12)
⇒ 1728 = 27x³ -64y³ - 2592
⇒ 27x³ - 64y³ = 1728 + 2592
⇒ 27x³ - 64y³ = 4320
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