if 3^x=5^y=75^2, show that xy=2(2x+y)
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1
Answer:
Given,
3
x
=5
y
=75
z
3
x
=5
y
=75
z
=k
⇒3=k
x
1
,5=k
y
1
,75=k
z
1
5
2
×3=k
z
1
(k
y
1
)
2
×(k
x
1
)=k
z
1
By comparing powers
⇒
y
2
+
x
1
=
z
1
xy
2x+y
=
z
1
∴z=
2x+y
xy
[henceproved]
Step-by-step explanation:
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