Math, asked by ash09954, 11 months ago

If 3^x + 64 = 2^6 + (√3)^8 , find the value of x

Answers

Answered by ankanr38
2

Answer:

X will be 48 so X will be 48 and your answer will be 48

Answered by harendrachoubay
3

The value of x is equal to 4.

Step-by-step explanation:

We have,

3^x+64=2^6+(\sqrt{3})^8

To find, the value of x = ?

3^x+64=2^6+(\sqrt{3})^8

3^x+64=64+(\sqrt{3})^8

3^x=(\sqrt{3})^8

(\sqrt{3}^2)^x=(\sqrt{3})^8

\sqrt{3}^{2x}=(\sqrt{3})^8

Using the exponential identity,

(a^{m})^n=a^{mn}

\sqrt{3}^{2x}=(\sqrt{3})^8

Comparing the powers of \sqrt{3}, we get

⇒ 2x = 8

⇒ x = \dfrac{8}{2} = 4

The value of x = 4

Thus, the value of x is equal to 4.

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