Question

if 3^x+8 = 27^2x+1, find the value of x​

Answer 1

$heya \\ \\ \\ \\ 3 {}^{x + 8} = 3 {}^{3 \times (2x + 1)} \\ \\ \\ 3 {}^{x + 8} = 3 {}^{6x + 3} \\ \\ \\ \\ now \: compare \: powers \: of \: 3 \\ \\ \\ x + 8 = 6x + 3 \\ \\ \\ - 5x = - 5 \\ \\ \\ x = 1$

Answer 2

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