Math, asked by vs7009212023, 1 month ago

. If 3+x,x-3,-2x+12 are in A.P., then value of x

-7
7
0
21​

Answers

Answered by dubeypunam446
1

Answer:

(3 + X) + (X - 3) + (- 2 X + 12)

=12

Answered by barmansuraj489
0

Concept:

A succession of words with a common difference amongst them that has a linear relation is known as an arithmetic progression. A series of words known as an arithmetic progression (AP) have identical differences. A progression in which the difference between two subsequent words is constant is known as an arithmetic progression (AP).

Given:

We have been given that the A.P. series is 3+x,x-3,-2x+12.

Find:

We have to find the value of x.

Solution:

According to the question,

The A.P. series is 3+x,x-3,-2x+12.

Now,

x-3=-2x+12-3-x\\= > 4x=12\\= > x=3

Hence, the value of x=3.

#SPJ3

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