Question

If 3+x,x-3,-2x+12 are in A.P., then value of x is:​

Answer 1

Answer:

12 is the value of x

Step-by-step explanation:

Answer 2

Given: $3+x$ , $x-3$ and $-2x+12$ are in A.P.

To find: Value of $x$

Solution: According to the given question,

$3+x$,  $x-3$ and $-2x+12$ form an A.P. which means the difference between these terms must be same, which is called the common difference (d ).

$= > (x-3) - (3+x) = (-2x+12) - (x-3)\\= > x - 3 - 3 - x = -2x + 12 - x + 3\\= > -6 = -3x + 15\\= > 3x = 15 + 6 = 21\\= > x = \frac{21}{3} = 7$

Hence, the value of x is 7.