Question

If 3^x + y = 243 and 22^x + y = 128, then find the value of x3 + y3 .

Answer 1

Answer:35

Step-by-step explanation:

Given

$3^{x+y}=243$

and $2^{2x+y}=128$

i.e. $3^{x+y}=3^5=243$

$\therefore \ x+y=5\quad \ldots(i)$

and $2^{2x+y}=2^7=128$

$2x+y=7\quad \ldots(ii)$

solving (i) and (ii) we get

$x=2,y=3$

thus $x^3+y^3=(2)^3+(3)^3=35$

Answer 2

Answer:

The answer is 35

Step-by-step explanation:

Hope this helps :>