If 3(x+y) = 27 and 3(x+y) = 81 then x =
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[tex]solution \\ \\ \\ given \: equations \\ \\ 3(x + y) = 27 \: \: ..... \: (1) \\ \\ 3(x + y) = 81 \: \: ...... \: \: (2) \: \\ \\ from \: eq \: 1 \: we \: get \: \\ \\ x \: = \: 9 - y \: \: ...... \: \: (3) \\ \\ now \: substitute \: eq \: 3 \: in \: 2 \\ \\ we \: get \\ \\ 3(9 - y + y) = 81
27 – 3y + y = 81
–2y = 54
y = –27
hence , y = –27
now substitute y's value in eq 3 , we get
x = 9 – (–27)
then
x = 36
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